969220. public static void Main() http://projecteuler.net/index.php?section=problems&id=1, http://projecteuler.net/index.php?section=problems&id=2, http://projecteuler.net/index.php?section=problems&id=3, ProblemSets/Project Euler Solutions (last edited 2012-05-31 06:16:44 by 123). Then, calculate the sum using an expanded formula which accounts for the multiplier, d. By applying the above formula to n=999 and d=3 and d=5 we get the sums for every third and fifth natural number. y=sum(range(0, 10, 5)) Integer divider2 = t/multiple2; } Take a break. My plan is to post a solution to all the ProjectEuler.net problems I have managed to solve. All my code is original work, not based on anyone elses code, although a couple of times I obtained the high-level approach from reading various literature on the web. - GitHub - comp0zr/Project-Euler-Solutions: Solutions for HackerRank's wonderful (and often mind-bending) expanded versions of the Project Euler (projecteuler.net) problem archive. k = 5 [edit] 27 5 + 84 5 + 110 5 + 133 5 = 144 5 . ((five * j) % 3 == 0)) for (var i = 0; i < num; i++) { Console.WriteLine("The sum of multiples of 3 and 5 number is " + (Result )); http://www.mathblog.dk/project-euler-prolog/, http://www.mathblog.dk/stopwatch-a-timing-function-in-c/. I hope you have found it useful and have learned from it. Leading a two people project, I feel like the other person isn't pulling their weight or is actively silently quitting or obstructing it. Almost all my solved problems also include a Python program (except for a few). You can see a whole lot of ideas right here http://www.mathblog.dk/programming-challenges/ The Project Euler solution programs listed above were benchmarked to see how much time it took to compute the answer. My solution code is first designed to run within an acceptable running time (not targeting absolute fastest code), and then heavily optimized for human clarity (both in terms of the code implementation and the underlying mathematical concepts). it is even more difficult to actually recommend something without knowning your current level. When the migration is complete, you will access your Teams at stackoverflowteams.com, and they will no longer appear in the left sidebar on stackoverflow.com. The sum of these multiples is 23. C and C++ are unsafe because of the lack of array bounds checking, having signed integer overflow, and having tons of easily invoked undefined behaviors. In In Mathematica, I make heavy use of nested expressions, functional programming core functions like Map and Select, and aggregation functions like Total, Length, Sum. Among the web, this is perhaps the largest collection of Project Euler solutions in the Java programming language. The first advice here, is to have fun. So, we need to find a more efficient way of calculating this sum without looping. Though I know they would be giving the editorials out when the contest ends, I do not find their explanation as helpful as I have found your explanation for the project euler problems. There are multiple methods for finding the solution for this problem. 1 I have started solving problems on code-chef also. }while(index<=divider1); To convert your symbolic type to char array, use char (prod) instead of num2str (prod) 0 If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. ID. Finding features that intersect QgsRectangle but are not equal to themselves using PyQGIS. Explaining solution of Project Euler problem #5. As is your question lacks enough context to make it useful for future research. The second advice I will give you is that the most important thing to learn in order to solve problems like these are to think abstractly. Solution to Project Euler 1. However, this can be written much shorter using the modulo operator, which finds the remainder of the integer division. >>> print( %s seconds % (time.time() start_time)) total = total + 0; is a no-op. Heatmap I stopped working on Project Euler problems around the time they released 617. It was proposed by Leonhard Euler in 1769. . Each problem that I solved always includes a Java program. Connect and share knowledge within a single location that is structured and easy to search. Problem 2: Find the sum of all the even-valued terms in the Fibonacci sequence which do not exceed one million. it is important to note the parenthesis around p/n, if these are not there, the result will deviate since the program n*below/n = n, which is different from n*(below/n). >>> x = 0 You will come back with new and fresh ideas. Problem 1: Add all the natural numbers below 1000 that are multiples of 3 or 5. Contribute to Yyandrakk/ProjectEulerRust development by creating an account on GitHub. do{ System.out.print(index); The natural numbers below 10 that are multiples of 3 or 5 results are 3, 5, 6 and 9. Go . It is mostly intact except for a few fixes (i) for compilation errors and typos in comments; and (ii) to change . So I think U suggested me to first study all the Programming concepts(Frm the book U suggested for efficient progrmm. is clearly more than that. Result = three_total + five_total; Find the sum of all the multiples of 3 or 5 below 1000. print(z). All problems from #1 to #100 have a Java and Python program, and problems #1 to #50 have a Mathematica program. The iterative approach simply wont work fast enough, but the presented closedform will. Updated: February 26, 2018. And no you havent offended me by asking this kind of question. } This probably comes from a mixture of trying some of the problems, learning a bit of new theory while trying to solve it (google is your friend here), and reading math. On the other hand, a horizontal spacing around operators, braces, etc is necessary. Toggle Main Navigation. The following for loop is easier to understand: Concerning your comments on +=, did you accidentally use total += total + j? >>> My code tends to be quite short: one-liners are very common, and typically the solution is less than 5 lines of code. Problem 1. Plz Pardon me for this unrelated post thanks mr Kristian for such best explanation with different approaches. Oracle Java 10.0.2+13 (64-bit), Intel Core i5-4690 (Haswell) 3.50GHz, Windows 8.1 Pro (64-bit). To calculate the Nth triangular number you add the first N numbers: 1 + 2 + 3 + + N. If you want to find the 100th triangular number, you begin the long and laborious addition of the first 100 numbers. It should be a local variable. The sum of numbers divisible by 6 or 10 between 1 and 9999 is 12495006 namespace MapReduce Little by little, vague ideas to solve the problem will arise until, eventually, you are able to see it clearly. [] rather than a pure math solution. How do I make kelp elevator without drowning? } Solution to Project Euler Problem 1: Multiples of 3 and 5 - If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. etc. Unfortunately due to Pythons slow performance on arrays and machine-word-sized integer values, many solutions are not worth the time to run it compared to the Java implementations. }. Numerous solutions contain a detailed mathematical proof to justify why the implemented algorithm is correct. 1. The sum of these numbers is 3 + 5 + 6 + 9 = 23. Find the sum of all the multiples of 3 or 5 below 1000. Solved By. Sample code (problem 117) (most other solutions are many times longer): { 1 Link If you do class (prod) you will see that it is a double data type. My Account; My Community Profile; Link License Many problems additionally have a Mathematica and Haskell program. The compiler will most likely throw that line away, but better don't include it. } } However, it can still be observed that Python is generally 10 to 30 slower than Java for pure number-crunching code. The 310 solved problems (that's level 12) had an average difficulty of 32.6% at Project Euler and I scored 13526 points (out of 15700 possible points, top rank was 17 out of 60000 in August 2017) at Hackerrank's Project Euler+. So instead of the previous check we can write. [] the project euler 1 solution. The whole code can be written as, int result = 0; I solve Project Euler problems to practice and extend my math and programming skills, all while having fun at the same time. i+=3; Solution to Project Euler problem 1 in C#, The solution to problem 1 of Project Euler: Find the sum of all the multiples of 3 or 5 below 1000 The power method takes two integers, and , as parameters and returns the integer result of 2)Count of Subset Sum Problem (1 HackerRank >Solutions I applied through college or university I applied through college or. do For a more efficient but more maths focused solution see the MathBlog post on the topic. Feel free to make comments and correct mistakes. Pseudocode, stub code . The teacher was surprised when he looked at the tablet to find the correct answer 5,050 with no steps in the calculation. . Custom algorithms like the sieve of Eratosthenes, especially ones most naturally expressed in terms of imperative state updates, are difficult to implement correctly or efficiently in Haskell. The j loop can be sped up 5-fold by incrementing j by five: Along the same line, the i loop can be rewritten as. All the numbers listed in the table below are in seconds, and these computing environments were used: GitHub: luckytoilet: projecteuler-solutions, Stephan Brumme: Project Euler C++ solutions, Overview of Project Nayuki software licenses. However, lets explore the problem a bit more. if(((i%3)==0||(i%5)==0)) When a problem can be solved in a purely functional way without imperatively updating variables, my Haskell solution will be structured very similarly to my Mathematica solution. Project Euler problems solution in C. This repository contains my solutions to Project Euler problem 1 to 10 written in C. There is some use of C preprocessor macros in code. The problems archives table shows problems 1 to 804. If what you are really looking for is some programming challenges to throw yourself at, there are a lot of options which are less math focused then Project Euler, not that I will try to discourage you by any means. Also I study the numerical bounds carefully to avoid integer overflow, and use the most reasonably narrow type for speed (choosing between int, long, or BigInteger). z=int(x)+int(y) Plz reply a relatively simple pattern is obtained: The sum of numbers divisible by 6 or 10 between 1 and 9 is 6 I am trying the problems in August Challenge. Thanks. return j; Browse other questions tagged, Start here for a quick overview of the site, Detailed answers to any questions you might have, Discuss the workings and policies of this site, Learn more about Stack Overflow the company. In general, sum the numbers less than 1000 that are divisible by 3 (3, 6, 9, 12, 15, ) or 5 (5, 10, 15, ) and subtract those divisible 3 and 5 (15, 30, 45, ). As you can see, for such small problems, it takes less than a millisecond on my computer to solve, so there really is not need to find faster solutions. With python we can express the sum like : The first problem of project Euler found here, below is the problem for quick lookup. Improve your writing skills in 5 minutes a day with the Daily Writing Tips email newsletter. If you apply those comments above, you end up with. Project Euler problem #1 solution in C [closed] By maria Posted on September 29, 2019. total = total + 0 doesn't change total at all. Why not floor(1000/3) = 333. If you printf a unsigned int, you must use %u, not %lu, since the latter is meant for unsigned long int. And the output of the algorithm is once again. I am stuck with the problem DRANGE (Range of Data). Updated: July 29, 2022 Training Time: 1 Minute Overseen by: Archangel Macsika. Glasgow Haskell Compiler 7.10.3, compiling with -O option to 64-bit executables, Intel Core i5-4690 (Haswell) 3.50GHz, Ubuntu Linux 16.04 (64-bit). Also, my Java solutions tend to be long due to types on every variable, lots of custom code, and low-level loops instead of higher-order functions. Become familiar with the notation and give your self some problems where you push yourself a bit. Now Gauss had a rectangle with 100 rows containing 101 beans each. 233168 Project Euler Problem 1. -Project Euler problem #1. Make it j<1000; 2nd problem with your solution is that you are adding the multiples of 3 and 5 i.e all multiples of 15 ( less than 1000) twice. Your explanation is really easy to understand for novice like me. The simpler solution is to just loop from 0 to 999 and test each number with the % modulus operator; if the outcome is 0, the left-hand side number is divisible by the right-hand side argument. The description of problem 1 on Project Euler reads. I promise I will include cool tidbits for you. I understand. Python solutions are tested to work on CPython 3.4.3. Using the mod operator to check for even divisibility (a zero remainder after division) we sum those integers, i, that are divisible by 3 or 5. System.out.println(Sum : +sum); C Clojure Go Haskell JavaScript Python Ruby Rust Scheme. Just have patience and perseverance. Together with the sum () built-in function and a generator expression, that becomes: sum (x for x in range (1000) if x % 3 == 0 or x % 5 == 0) This package contains at least 205 solutions in Java, at least 200 in Python, at least 125 in Mathematica, and at least 95 in Haskell. Project Euler Problem 3 Solution. This solution is much faster than using brute force which requires loops. }. >>> Otherwise I cannot reproduce your behaviour. Project Euler Problem 1 Solution with C# Raw ProjectEuler.P1.cs This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. So lets look at the numbers divisible by n=3: The trick is to express the sum by other means, and in this case the sum. index++; In our Python function, sumn() (shown below), this is accomplished by using the floor function on n divided by d to find the number of nonzero terms. I don't think anyone finds what I'm working on interesting. Your first for loop uses an optimization, your second doesn't. I can recommend khanacademy.org which is a great learning place that will take you far. ), and possibly improve the speed (it's . Here, we are initializing our function E_116 () which holds the logic of the solution to the problem.The function E_116 () has two parameters i = number of black coloured square tiles covered by the new coloured (red, green or blue) tiles and k = total number of black coloured square tiles. Updated: February 26, 2018. Found footage movie where teens get superpowers after getting struck by lightning? Problem 1 Problem one asks competitors to complete the following mathematical question: If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6, and 9. So you are meant to use coding not your head ? { Modified 7 years, 1 month ago. SumDivisbleBy(3, 999) + SumDivisbleBy(5, 999) SumDivisbleBy(15, 999), You could use Linq to do that: Enumerable.Range(1, 999).Where(item => item % 3 == 0 || item % 5 == 0).Sum(), A nice MATLAB-solution is: Excuse me, but how it can be that N=p/n when N=995, p=999, and n=5? Project Euler Problem 1 Statement If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. http://www.math.brown.edu/~jhs/frint.html, umi dont know why no ones mentioned it yet but why not use modulo? Happy coding!!! Without going into details about what happens if the numbers become greater than what can be stored in an integer or long lets have a look at the scalability of the algorithms. The sum of these multiples is 23. This is Problem 5, finding the smallest multiple. I used Mathematica for many of the earlier problems, because compactness and convenient library functions were more important than running time or memory. Func MultiplesOf = (x, range) => while (five * j < 995); This problem involves finding the sum of two related arithmetic sequences. Ans=x+y-z. The C code was written by November 2014 at the latest. Are cheap electric helicopters feasible to produce? Lacks concrete context: Code Review requires concrete code from a project, with sufficient context for reviewers to understand how that code is used. 'It was Ben that found it' v 'It was clear that Ben found it'. if (i % 3 == 0 || i % 5 == 0) { However, we need to put something clever inside the SumDivisbleBy function, otherwise we have an even slower solution. Sign In to Your MathWorks Account Sign In to Your MathWorks Account; Access your MathWorks Account. I just want to ask where should I start from,(Confused)As theres lot just then programming U hv to learn Data,Ada etc then U must knw Maths Thanks for the tipsVery usefulgave me a direction to go upon. The sum of these multiples is 23. The description of problem 1 on Project Euler reads Find the sum of all the multiples of 3 or 5 below 1000. Have a nice day. There are a whole lot of number theory in them, but also some linear algebra, some statistics and so on. Learn more about bidirectional Unicode characters . Heres how he figured it out: The sequence [1, 3, 6, 10, 15, ] is called the triangular numbers and count objects arranged in an equilateral triangle. Occasionally I write imperative code in Mathematica, usually for unbounded searching. The sum of numbers divisible by 3 or 5 between 1 and 9999 is 23331668 Problem. I like using Java because it is fast, safe, and expressive. Thanks for the help. { The sum of numbers divisible by 3 or 5 between 1 and 999999 is 233333166668 Custom data structures like graphs are difficult to express cleanly in Mathematica. Solutions to the first 40 problems in functional Python. using c = System.Console; public class Test { Find the sum of all the multiples of 3 or 5 below 1000. If I was aiming for raw execution speed, writing comparable code in C or C++ would probably run 3 as fast as Java. jumlah=jumlah+5; The sum of these multiples is 23. Does a creature have to see to be affected by the Fear spell initially since it is an illusion? where n is the divisor, and p is the greatest number we want to check. Just found this site which is apparently devoted to solutions for the Euler problem set, in python, with a functional flavor. I am new to C# and I cannot figure out ow to call each function ( Solve() and SumDivisibleBy() ) from my static void Main() method. Being a cs undergrad I am pretty sure you are already having quite a few courses in different subjects. Tho you could also refactor that to a single fx and then do a yield return. sum=sum+index5; //Scanner scan = new Scanner(System.in); Some solution code contains a detailed mathematical proof of correctness. One of my personal favorites for that topic is this one 15)? Project Euler is a series of challenging mathematical/computer programming problems that will require more than just mathematical insights to solve. x=sum(range(0, 1000, 3)) Mathematically speaking, this problem is pretty easy. } Unable to edit the page? Problem 2: Find the sum of all the even-valued terms in the Fibonacci sequence which do not exceed one million. Find the sum of all the multiples of 3 or 5 below 1000. I dont know why it doesnt work for you. Non-anthropic, universal units of time for active SETI. Another solution would be to find the sum of all numbers divisible by three, and the sum of all numbers divisible by 5. It is not currently accepting answers. Pretty simple to brute force, but more gently solutions are not that easy to understand, and I'm not talking about programming issue, but math-affiliated. The best answers are voted up and rise to the top, Not the answer you're looking for? Does the Fog Cloud spell work in conjunction with the Blind Fighting fighting style the way I think it does? {1-1000} [233168] Where is the problem? For each number, check if it's divisible by either 3 or 5. The sum of numbers divisible by 6 or 10 between 1 and 99 is 1206 Note that for problems involving non-whole numbers, I try to use exact integer arithmetic or fractions as much as possible, which ensures that the solution is provably correct. Over time, the Python code was adapted to fit the characteristics of the language such as using idiomatic/Pythonic approaches, tweaking or changing algorithms to increase speed (whereas Java can sometimes get away with less efficient but simpler algorithms), and making heavy use of generators. Then run with a command like java p001, and the answer will be printed to standard output. Thanks for replying Find the sum of all the multiples of 3 or 5 below 1000. )and for strengthening math go from High School level to beyondand then switch to solving. I tried simplifying this but Im getting the wrong number and I dont know why. int five = 5; We can adapt this formula to count the numbers only divisible by d to a specific upper bound, such as n=33, d=3, as shown in the following example. x % 3 == 0 However, programming is more than the language, there is a whole lot to learn about algorithms and data structures which is almost generic regardless of the language you program in. 3 more parts. Although mathematics will help you arrive at elegant and efficient methods, the use of a computer and programming skills will be required to solve most problems. Data Science Project Euler RStats This first Euler problem provides a gentle introduction to solving mathematical problems with code. Here's a complete walkthrough to Project Euler problem 1. Thank you for a great question which also warrants a great answer. Stack Overflow for Teams is moving to its own domain! As a result I strongly avoid any floating-point arithmetic at all, unless there is no other reasonable way (that I know of) to solve the problem. Here's the math behind it. console.log(total). can you please suggest me other sites where i can practice c pragramming Would you pleas post the entire compilable C# source for the optimized solution ? if i % 3 == 0 or i % 5 == 0: The first 6 chapters are available here Sign up for the Mathblog newsletter, and get updates every two weeks. On this page is the solution for Problem 1 of Project Euler. i++; It's quite a simple problem, You can get some . do {1-10000} [23331668] Also, Mathematica uses a lot of memory to store an array of integers because it doesnt have packed fixed-width integers. A formula attributed to Carl Friedrich Gauss will calculate the sum of the first n natural numbers. Did Dick Cheney run a death squad that killed Benazir Bhutto? The sum of numbers divisible by 6 or 10 between 1 and 999 is 124506 Anyway, here is what I ended up []. Most mathematical activity involves the discovery of properties of . {. I am afraid I cant help you out on that one right now. Welcome to my solutions for Project Euler. I write Mathematica code in a rather plain style, using only [] for function application (not @ or //), avoid pattern processing, and avoid declaring functions with the #-and-& syntax. What should I do? The style of using generators/filters/itertools can be considered about halfway between Javas imperative style and {Haskell or Mathematica}s functional style. Problem 1: Multiples of 3 and 5 If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. my JS code(runs fast enough)-, var num = 1000; Solutions to the first 40 problems in functional Python. Solution took 0 ms, ##the answer will be 234168, not 233168 as given here, Solution to Project Euler, Problem 1, using Python (v.3.6.1), >>> import time It should be a local variable. Please explain what that code is intended to do, briefly in the question title, and in more depth in the question body. for (int i = 1; i < 1000; i++) { Mathematica provides easy access to prime numbers, big integers, high-precision floats, fractions, continued fractions, and more. { The game of bowling, or tenpin, sets 10 pins in a equilateral triangular form: one pin in the first row through 4 pins in the last row. } System.out.println(Beginning); Simply go through all the numbers from 1 to 1000 (non-inclusive). This is because it has many useful built-in mathematical functions (like prime testing) and objects (like fractions) that would require manual effort to implement in Java. I think there are two pieces of advice I can give you right now. These pieces of code are interesting for a couple of reasons: One is that it caters to programmers who prefer to read Python code over Java due to familiarity with the language. sum=sum+index3; That said, ProjectEuler problems are more about math than programming. Newbie there and doing UG in CS(2nd yr)(U asked my level-novice++). if(j%3!=0) A solution can be implemented quickly and intuitively by using an iterative approach that loops through a range of integers between 1 and 999. Earliest sci-fi film or program where an actor plays themself. To elaborate on these points, I will compare it to other programming languages: Python and Mathematica are slow for basic integer arithmetic (~1/30 of Java speed) because they natively use bigint and are also dynamically typed. And the result of running the code is, 1 01.02.2021. Your first for loop uses an optimization, your second doesn't. That's asymmetrical. >>> for i in range(1000): Stack Exchange network consists of 182 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers. solutions of the Diophantine equation a 6 + b 6 = c 6 . Etc, Output of the results using extension of RosettaCode in C#, https://rosettacode.org/wiki/Sum_multiples_of_3_and_5#C.23, The sum of numbers divisible by 3 or 5 between 1 and 9 is 23 I found this book, http://www.amazon.com/Friendly-Introduction-Number-Theory-Edition/dp/0321816196/, It is pretty expensive, but from the chapter I have skimmed, it looks pretty good. Reduces the iteration from 1000 times to (333 +200) = 533. i.e. Find the sum of all the multiples of 3 or 5 below the provided parameter value number. Project Euler (7 Part Series) 1 Project Euler #1 - Multiples of 3 and 5 2 Project Euler #2 - Even Fibonacci numbers . Is the copious amount of whitespace intended? We could define a function that did this. Uva online judge, code foces as well as code chef have some really interesting problems I think. , I was looking for something about number theory which is a very integral part of the Project Euler problems. Double types in matlab have 16 decimal digits precision and 100! This solution can handles the sum below any given number almost equally fast, if the sum can be stored in an integer. Many Haskell solutions depend on my shared math library module: EulerLib.hs. Ask Question Asked 7 years, 1 month ago. total += i ; This is my python solution to the first problem on Project Euler: n = 1 rn = 0 while n < 1000: if n%3 == 0 or n%5 == 0: rn += n n = n + 1 print (rn) I would like to find a way to keep everything in this python code to as little number of lines as possible (maybe even a one liner?? Viewed 329 times 0 $\begingroup$ Here is the problem. So you will need to find a way to compress the data ranges. To review, open the file in an editor that reveals hidden Unicode characters. linear algo. However on the flip side, I prefer to solve a problem in Mathematica first if its possible. Thanks anyways. Note: I've written all of my solutions in Java, but the concept is the same in any language. However the geometric approach has a constant computation time, which is expressed as O(1), which is obviously better . Thus the sequences for any number divisible by n can be written as n*N*(N+1)/2. Its me again, thanks for your feedback.I solved the problem and your code is fine.
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